convert epoch using date command
date -d ‘<Unix epoch> <epoch date> sec’
e.g. date -d ‘1970-01-01 988822888 sec’ would dated “Wed May 2 17:31:28 MYT 2001”
20080430 :
get a particular date in epoch, e.g. date -d ‘Apr 30 2008 00:00:00’ ‘+%s’
date -d ‘<Unix epoch> <epoch date> sec’
e.g. date -d ‘1970-01-01 988822888 sec’ would dated “Wed May 2 17:31:28 MYT 2001”
20080430 :
get a particular date in epoch, e.g. date -d ‘Apr 30 2008 00:00:00’ ‘+%s’
why not use the following?
date -d ‘@’
e.g. date -d @1216024547
Mon Jul 14 10:35:47 CEST 2008
Hi,
I trying to convert epoch seconds to D/M/Y H:M:S.s format. I am passing epoch seconds as an argument to perl file.
Inside perl file, the code looks like this:
my $epoch = $ARGV[0];
open(OUT, “>c:/dateResultFile.txt”);
my $str = “date -d ‘1970-01-01 $epoch sec'” ;
print OUT “$str\n”;
close(OUT);
when i executed this code, i am getting i am not getting the date as i expected.
Please suggest me the solution.
$ date +%s -d”Jan 1, 1980 00:00:01″
date: 0551-402 Invalid character in date/time specification.
Usage: date [-u] [+”Field Descriptors”]
System used is AIX…this doesn’t work